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(5x-3)=(2x+8)+(x-1)
We move all terms to the left:
(5x-3)-((2x+8)+(x-1))=0
We get rid of parentheses
5x-((2x+8)+(x-1))-3=0
We calculate terms in parentheses: -((2x+8)+(x-1)), so:We get rid of parentheses
(2x+8)+(x-1)
We get rid of parentheses
2x+x+8-1
We add all the numbers together, and all the variables
3x+7
Back to the equation:
-(3x+7)
5x-3x-7-3=0
We add all the numbers together, and all the variables
2x-10=0
We move all terms containing x to the left, all other terms to the right
2x=10
x=10/2
x=5
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