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2(5y+2)=2(5y+2)=14
We move all terms to the left:
2(5y+2)-(2(5y+2))=0
We multiply parentheses
10y-(2(5y+2))+4=0
We calculate terms in parentheses: -(2(5y+2)), so:We get rid of parentheses
2(5y+2)
We multiply parentheses
10y+4
Back to the equation:
-(10y+4)
10y-10y-4+4=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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