6(x-3)+5x=1/2(x+24)+12

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Solution for 6(x-3)+5x=1/2(x+24)+12 equation:



6(x-3)+5x=1/2(x+24)+12
We move all terms to the left:
6(x-3)+5x-(1/2(x+24)+12)=0
Domain of the equation: 2(x+24)+12)!=0
x∈R
We add all the numbers together, and all the variables
5x+6(x-3)-(1/2(x+24)+12)=0
We multiply parentheses
5x+6x-(1/2(x+24)+12)-18=0
We multiply all the terms by the denominator
5x*2(x+24)+12)+6x*2(x+24)+12)-(1-18*2(x+24)+12)=0
We add all the numbers together, and all the variables
5x*2(x+24)+12)+6x*2(x+24)+12)-(1-18*2(x=0
Wy multiply elements
10x^2(x+12)+6x*2(x+24)-18*2(x+12)-(1=0
We add all the numbers together, and all the variables
10x^2(x+12)+6x*2(x+24)-18*2(x+12)=0
Wy multiply elements
10x^2(x+12)+12x^2(x-36x(x=0

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