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2(5x+1)+3=5(2x+1)
We move all terms to the left:
2(5x+1)+3-(5(2x+1))=0
We multiply parentheses
10x-(5(2x+1))+2+3=0
We calculate terms in parentheses: -(5(2x+1)), so:We add all the numbers together, and all the variables
5(2x+1)
We multiply parentheses
10x+5
Back to the equation:
-(10x+5)
10x-(10x+5)+5=0
We get rid of parentheses
10x-10x-5+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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