2(5j-1)=3(j+11)

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Solution for 2(5j-1)=3(j+11) equation: 



2(5j-1)=3(j+11)

We move all terms to the left:

2(5j-1)-(3(j+11))=0

We multiply parentheses

10j-(3(j+11))-2=0



We calculate terms in parentheses: -(3(j+11)), so:

3(j+11)

We multiply parentheses

3j+33

Back to the equation:

-(3j+33)



We get rid of parentheses

10j-3j-33-2=0

We add all the numbers together, and all the variables

7j-35=0

We move all terms containing j to the left, all other terms to the right

7j=35

j=35/7

j=5

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