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5/6t+7/8t=164
We move all terms to the left:
5/6t+7/8t-(164)=0
Domain of the equation: 6t!=0
t!=0/6
t!=0
t∈R
Domain of the equation: 8t!=0We calculate fractions
t!=0/8
t!=0
t∈R
40t/48t^2+42t/48t^2-164=0
We multiply all the terms by the denominator
40t+42t-164*48t^2=0
We add all the numbers together, and all the variables
82t-164*48t^2=0
Wy multiply elements
-7872t^2+82t=0
a = -7872; b = 82; c = 0;
Δ = b2-4ac
Δ = 822-4·(-7872)·0
Δ = 6724
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6724}=82$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(82)-82}{2*-7872}=\frac{-164}{-15744} =1/96 $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(82)+82}{2*-7872}=\frac{0}{-15744} =0 $
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