(7x-38)=(3x-2)

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Solution for (7x-38)=(3x-2) equation: 



(7x-38)=(3x-2)

We move all terms to the left:

(7x-38)-((3x-2))=0

We get rid of parentheses

7x-((3x-2))-38=0



We calculate terms in parentheses: -((3x-2)), so:

(3x-2)

We get rid of parentheses

3x-2

Back to the equation:

-(3x-2)



We get rid of parentheses

7x-3x+2-38=0

We add all the numbers together, and all the variables

4x-36=0

We move all terms containing x to the left, all other terms to the right

4x=36

x=36/4

x=9

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