2(4a-3)=3(7+3a)

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Solution for 2(4a-3)=3(7+3a) equation:



2(4a-3)=3(7+3a)
We move all terms to the left:
2(4a-3)-(3(7+3a))=0
We add all the numbers together, and all the variables
2(4a-3)-(3(3a+7))=0
We multiply parentheses
8a-(3(3a+7))-6=0
We calculate terms in parentheses: -(3(3a+7)), so:
3(3a+7)
We multiply parentheses
9a+21
Back to the equation:
-(9a+21)
We get rid of parentheses
8a-9a-21-6=0
We add all the numbers together, and all the variables
-1a-27=0
We move all terms containing a to the left, all other terms to the right
-a=27
a=27/-1
a=-27

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