6(v+3)=-2(2v-5)+4v

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Solution for 6(v+3)=-2(2v-5)+4v equation: 



6(v+3)=-2(2v-5)+4v

We move all terms to the left:

6(v+3)-(-2(2v-5)+4v)=0

We multiply parentheses

6v-(-2(2v-5)+4v)+18=0



We calculate terms in parentheses: -(-2(2v-5)+4v), so:

-2(2v-5)+4v

We add all the numbers together, and all the variables

4v-2(2v-5)

We multiply parentheses

4v-4v+10

We add all the numbers together, and all the variables

10

Back to the equation:

-(10)



We add all the numbers together, and all the variables

6v+8=0

We move all terms containing v to the left, all other terms to the right

6v=-8

v=-8/6

v=-1+1/3

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