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3/5(4a-5)-5/12(3a-4)=1/6
We move all terms to the left:
3/5(4a-5)-5/12(3a-4)-(1/6)=0
Domain of the equation: 5(4a-5)!=0
a∈R
Domain of the equation: 12(3a-4)!=0We add all the numbers together, and all the variables
a∈R
3/5(4a-5)-5/12(3a-4)-(+1/6)=0
We get rid of parentheses
3/5(4a-5)-5/12(3a-4)-1/6=0
We calculate fractions
(216a3/(5(4a-5)*12(3a-4)*6)+(-150a4/(5(4a-5)*12(3a-4)*6)+(-60a^24/(5(4a-5)*12(3a-4)*6)=0
We calculate terms in parentheses: +(216a3/(5(4a-5)*12(3a-4)*6)+(-150a4/(5(4a-5)*12(3a-4)*6)+(-60a^24/(5(4a-5)*12(3a-4)*6), so:
216a3/(5(4a-5)*12(3a-4)*6)+(-150a4/(5(4a-5)*12(3a-4)*6)+(-60a^24/(5(4a-5)*12(3a-4)*6
We do not support eapression: a^24
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