2(3y+4)+4y=48

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Solution for 2(3y+4)+4y=48 equation: 



2(3y+4)+4y=48

We move all terms to the left:

2(3y+4)+4y-(48)=0

We add all the numbers together, and all the variables

4y+2(3y+4)-48=0

We multiply parentheses

4y+6y+8-48=0

We add all the numbers together, and all the variables

10y-40=0

We move all terms containing y to the left, all other terms to the right

10y=40

y=40/10

y=4

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