-10=(-8+b)/2

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Solution for -10=(-8+b)/2 equation: 



-10=(-8+b)/2

We move all terms to the left:

-10-((-8+b)/2)=0

We add all the numbers together, and all the variables

-((b-8)/2)-10=0

We multiply all the terms by the denominator


-((b-8)-10*2)=0



We calculate terms in parentheses: -((b-8)-10*2), so:

(b-8)-10*2

We add all the numbers together, and all the variables

(b-8)-20

We get rid of parentheses

b-8-20

We add all the numbers together, and all the variables

b-28

Back to the equation:

-(b-28)



We get rid of parentheses

-b+28=0

We add all the numbers together, and all the variables

-1b+28=0

We move all terms containing b to the left, all other terms to the right

-b=-28

b=-28/-1

b=+28

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