2(3y+3)=42

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Solution for 2(3y+3)=42 equation: 



2(3y+3)=42

We move all terms to the left:

2(3y+3)-(42)=0

We multiply parentheses

6y+6-42=0

We add all the numbers together, and all the variables

6y-36=0

We move all terms containing y to the left, all other terms to the right

6y=36

y=36/6

y=6

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