n(n-1)(n-2)/6=120

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Solution for n(n-1)(n-2)/6=120 equation: 



n(n-1)(n-2)/6=120

We move all terms to the left:

n(n-1)(n-2)/6-(120)=0

We multiply parentheses ..

n(+n^2-2n-1n+2)/6-120=0

We multiply all the terms by the denominator


n(+n^2-2n-1n+2)-120*6=0

We add all the numbers together, and all the variables

n(+n^2-2n-1n+2)-720=0

We multiply parentheses

n^3-2n^2-1n^2+2n-720=0

We do not support enpression: n^3

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