2(3x-5)=2(x+2)+10

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Solution for 2(3x-5)=2(x+2)+10 equation: 



2(3x-5)=2(x+2)+10

We move all terms to the left:

2(3x-5)-(2(x+2)+10)=0

We multiply parentheses

6x-(2(x+2)+10)-10=0



We calculate terms in parentheses: -(2(x+2)+10), so:

2(x+2)+10

We multiply parentheses

2x+4+10

We add all the numbers together, and all the variables

2x+14

Back to the equation:

-(2x+14)



We get rid of parentheses

6x-2x-14-10=0

We add all the numbers together, and all the variables

4x-24=0

We move all terms containing x to the left, all other terms to the right

4x=24

x=24/4

x=6

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