2(3x-2)+2(2x+2)=3x-56

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Solution for 2(3x-2)+2(2x+2)=3x-56 equation: 



2(3x-2)+2(2x+2)=3x-56

We move all terms to the left:

2(3x-2)+2(2x+2)-(3x-56)=0

We multiply parentheses

6x+4x-(3x-56)-4+4=0

We get rid of parentheses

6x+4x-3x+56-4+4=0

We add all the numbers together, and all the variables

7x+56=0

We move all terms containing x to the left, all other terms to the right

7x=-56

x=-56/7

x=-8

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