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(x+1)(x+2)=x
We move all terms to the left:
(x+1)(x+2)-(x)=0
We add all the numbers together, and all the variables
-1x+(x+1)(x+2)=0
We multiply parentheses ..
(+x^2+2x+x+2)-1x=0
We get rid of parentheses
x^2+2x+x-1x+2=0
We add all the numbers together, and all the variables
x^2+2x+2=0
a = 1; b = 2; c = +2;
Δ = b2-4ac
Δ = 22-4·1·2
Δ = -4
Delta is less than zero, so there is no solution for the equation
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