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(1/3)a-12=(3/4)a+6
We move all terms to the left:
(1/3)a-12-((3/4)a+6)=0
Domain of the equation: 3)a!=0
a!=0/1
a!=0
a∈R
Domain of the equation: 4)a+6)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
(+1/3)a-((+3/4)a+6)-12=0
We multiply parentheses
a^2-((+3/4)a+6)-12=0
We multiply all the terms by the denominator
a^2*4)a+6)-((-12*4)a+6)+3=0
We add all the numbers together, and all the variables
a^2*4)a+6)-((-48)a+6)+3=0
Wy multiply elements
4a^3-48)a+6)+3=0
We do not support eapression: a^3
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