2(3x+3x)=3(x+6)

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Solution for 2(3x+3x)=3(x+6) equation: 



2(3x+3x)=3(x+6)

We move all terms to the left:

2(3x+3x)-(3(x+6))=0

We add all the numbers together, and all the variables

2(+6x)-(3(x+6))=0

We multiply parentheses

12x-(3(x+6))=0



We calculate terms in parentheses: -(3(x+6)), so:

3(x+6)

We multiply parentheses

3x+18

Back to the equation:

-(3x+18)



We get rid of parentheses

12x-3x-18=0

We add all the numbers together, and all the variables

9x-18=0

We move all terms containing x to the left, all other terms to the right

9x=18

x=18/9

x=2

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