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4(w+1)-1=2(2w-3)
We move all terms to the left:
4(w+1)-1-(2(2w-3))=0
We multiply parentheses
4w-(2(2w-3))+4-1=0
We calculate terms in parentheses: -(2(2w-3)), so:We add all the numbers together, and all the variables
2(2w-3)
We multiply parentheses
4w-6
Back to the equation:
-(4w-6)
4w-(4w-6)+3=0
We get rid of parentheses
4w-4w+6+3=0
We add all the numbers together, and all the variables
9!=0
There is no solution for this equation
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