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2(3x+1)=4(3-x)
We move all terms to the left:
2(3x+1)-(4(3-x))=0
We add all the numbers together, and all the variables
2(3x+1)-(4(-1x+3))=0
We multiply parentheses
6x-(4(-1x+3))+2=0
We calculate terms in parentheses: -(4(-1x+3)), so:We get rid of parentheses
4(-1x+3)
We multiply parentheses
-4x+12
Back to the equation:
-(-4x+12)
6x+4x-12+2=0
We add all the numbers together, and all the variables
10x-10=0
We move all terms containing x to the left, all other terms to the right
10x=10
x=10/10
x=1
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