(6+y)2=12(-2)

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Solution for (6+y)2=12(-2) equation: 



(6+y)2=12(-2)

We move all terms to the left:

(6+y)2-(12(-2))=0

We add all the numbers together, and all the variables

(y+6)2-(12(-2))=0

We add all the numbers together, and all the variables

(y+6)2+24=0

We multiply parentheses

2y+12+24=0

We add all the numbers together, and all the variables

2y+36=0

We move all terms containing y to the left, all other terms to the right

2y=-36

y=-36/2

y=-18

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