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5/2x-1-9/3x-2=0
Domain of the equation: 2x!=0
x!=0/2
x!=0
x∈R
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
5/2x-9/3x-3=0
We calculate fractions
15x/6x^2+(-18x)/6x^2-3=0
We multiply all the terms by the denominator
15x+(-18x)-3*6x^2=0
Wy multiply elements
-18x^2+15x+(-18x)=0
We get rid of parentheses
-18x^2+15x-18x=0
We add all the numbers together, and all the variables
-18x^2-3x=0
a = -18; b = -3; c = 0;
Δ = b2-4ac
Δ = -32-4·(-18)·0
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3}{2*-18}=\frac{0}{-36} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3}{2*-18}=\frac{6}{-36} =-1/6 $
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