2(3x+1)=128

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Solution for 2(3x+1)=128 equation: 



2(3x+1)=128

We move all terms to the left:

2(3x+1)-(128)=0

We multiply parentheses

6x+2-128=0

We add all the numbers together, and all the variables

6x-126=0

We move all terms containing x to the left, all other terms to the right

6x=126

x=126/6

x=21

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