-3(4v-1)+2v=9+2(2v-7)

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Solution for -3(4v-1)+2v=9+2(2v-7) equation: 



-3(4v-1)+2v=9+2(2v-7)

We move all terms to the left:

-3(4v-1)+2v-(9+2(2v-7))=0

We add all the numbers together, and all the variables

2v-3(4v-1)-(9+2(2v-7))=0

We multiply parentheses

2v-12v-(9+2(2v-7))+3=0



We calculate terms in parentheses: -(9+2(2v-7)), so:

9+2(2v-7)

determiningTheFunctionDomain
2(2v-7)+9

We multiply parentheses

4v-14+9

We add all the numbers together, and all the variables

4v-5

Back to the equation:

-(4v-5)



We add all the numbers together, and all the variables

-10v-(4v-5)+3=0

We get rid of parentheses

-10v-4v+5+3=0

We add all the numbers together, and all the variables

-14v+8=0

We move all terms containing v to the left, all other terms to the right

-14v=-8

v=-8/-14

v=4/7

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