2(v+4)=-4(5v-5)+8v

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Solution for 2(v+4)=-4(5v-5)+8v equation: 



2(v+4)=-4(5v-5)+8v

We move all terms to the left:

2(v+4)-(-4(5v-5)+8v)=0

We multiply parentheses

2v-(-4(5v-5)+8v)+8=0



We calculate terms in parentheses: -(-4(5v-5)+8v), so:

-4(5v-5)+8v

We add all the numbers together, and all the variables

8v-4(5v-5)

We multiply parentheses

8v-20v+20

We add all the numbers together, and all the variables

-12v+20

Back to the equation:

-(-12v+20)



We get rid of parentheses

2v+12v-20+8=0

We add all the numbers together, and all the variables

14v-12=0

We move all terms containing v to the left, all other terms to the right

14v=12

v=12/14

v=6/7

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