2(3u-1)+6u=6(u-2)+4u

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Solution for 2(3u-1)+6u=6(u-2)+4u equation: 



2(3u-1)+6u=6(u-2)+4u

We move all terms to the left:

2(3u-1)+6u-(6(u-2)+4u)=0

We add all the numbers together, and all the variables

6u+2(3u-1)-(6(u-2)+4u)=0

We multiply parentheses

6u+6u-(6(u-2)+4u)-2=0



We calculate terms in parentheses: -(6(u-2)+4u), so:

6(u-2)+4u

We add all the numbers together, and all the variables

4u+6(u-2)

We multiply parentheses

4u+6u-12

We add all the numbers together, and all the variables

10u-12

Back to the equation:

-(10u-12)



We add all the numbers together, and all the variables

12u-(10u-12)-2=0

We get rid of parentheses

12u-10u+12-2=0

We add all the numbers together, and all the variables

2u+10=0

We move all terms containing u to the left, all other terms to the right

2u=-10

u=-10/2

u=-5

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