6(z+5)=24+3z

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Solution for 6(z+5)=24+3z equation: 



6(z+5)=24+3z

We move all terms to the left:

6(z+5)-(24+3z)=0

We add all the numbers together, and all the variables

6(z+5)-(3z+24)=0

We multiply parentheses

6z-(3z+24)+30=0

We get rid of parentheses

6z-3z-24+30=0

We add all the numbers together, and all the variables

3z+6=0

We move all terms containing z to the left, all other terms to the right

3z=-6

z=-6/3

z=-2

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