3n-2(n+2)=11

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Solution for 3n-2(n+2)=11 equation: 



3n-2(n+2)=11

We move all terms to the left:

3n-2(n+2)-(11)=0

We multiply parentheses

3n-2n-4-11=0

We add all the numbers together, and all the variables

n-15=0

We move all terms containing n to the left, all other terms to the right

n=15

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