2(3t+1)=4(4t-2)

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Solution for 2(3t+1)=4(4t-2) equation: 



2(3t+1)=4(4t-2)

We move all terms to the left:

2(3t+1)-(4(4t-2))=0

We multiply parentheses

6t-(4(4t-2))+2=0



We calculate terms in parentheses: -(4(4t-2)), so:

4(4t-2)

We multiply parentheses

16t-8

Back to the equation:

-(16t-8)



We get rid of parentheses

6t-16t+8+2=0

We add all the numbers together, and all the variables

-10t+10=0

We move all terms containing t to the left, all other terms to the right

-10t=-10

t=-10/-10

t=1

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