4(7y-3)=12

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Solution for 4(7y-3)=12 equation: 



4(7y-3)=12

We move all terms to the left:

4(7y-3)-(12)=0

We multiply parentheses

28y-12-12=0

We add all the numbers together, and all the variables

28y-24=0

We move all terms containing y to the left, all other terms to the right

28y=24

y=24/28

y=6/7

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