6(4i+2)=4(4i+3)

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Solution for 6(4i+2)=4(4i+3) equation: 



6(4i+2)=4(4i+3)

We move all terms to the left:

6(4i+2)-(4(4i+3))=0

We multiply parentheses

24i-(4(4i+3))+12=0



We calculate terms in parentheses: -(4(4i+3)), so:

4(4i+3)

We multiply parentheses

16i+12

Back to the equation:

-(16i+12)



We get rid of parentheses

24i-16i-12+12=0

We add all the numbers together, and all the variables

8i=0

i=0/8

i=0

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