2(3r-4)=3-2(r+6)

Solution for 2(3r-4)=3-2(r+6) equation:

2(3r-4)=3-2(r+6)

We move all terms to the left:

2(3r-4)-(3-2(r+6))=0

We multiply parentheses

6r-(3-2(r+6))-8=0


We calculate terms in parentheses: -(3-2(r+6)), so:

3-2(r+6)

determiningTheFunctionDomain
-2(r+6)+3

We multiply parentheses

-2r-12+3

We add all the numbers together, and all the variables

-2r-9

Back to the equation:

-(-2r-9)


We get rid of parentheses

6r+2r+9-8=0

We add all the numbers together, and all the variables

8r+1=0

We move all terms containing r to the left, all other terms to the right

8r=-1

r=-1/8

r=-1/8