5(x-2)=15+3(x-1)

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Solution for 5(x-2)=15+3(x-1) equation: 



5(x-2)=15+3(x-1)

We move all terms to the left:

5(x-2)-(15+3(x-1))=0

We multiply parentheses

5x-(15+3(x-1))-10=0



We calculate terms in parentheses: -(15+3(x-1)), so:

15+3(x-1)

determiningTheFunctionDomain
3(x-1)+15

We multiply parentheses

3x-3+15

We add all the numbers together, and all the variables

3x+12

Back to the equation:

-(3x+12)



We get rid of parentheses

5x-3x-12-10=0

We add all the numbers together, and all the variables

2x-22=0

We move all terms containing x to the left, all other terms to the right

2x=22

x=22/2

x=11

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