2*(x+1)*(x+1)=0

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Solution for 2*(x+1)*(x+1)=0 equation: 



2(x+1)(x+1)=0

We multiply parentheses ..

2(+x^2+x+x+1)=0

We multiply parentheses

2x^2+2x+2x+2=0

We add all the numbers together, and all the variables

2x^2+4x+2=0

a = 2; b = 4; c = +2;
Δ = b2-4ac
Δ = 42-4·2·2
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{-4}{4}=-1$

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