2(3b+1)=2(2b+5)

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Solution for 2(3b+1)=2(2b+5) equation: 



2(3b+1)=2(2b+5)

We move all terms to the left:

2(3b+1)-(2(2b+5))=0

We multiply parentheses

6b-(2(2b+5))+2=0



We calculate terms in parentheses: -(2(2b+5)), so:

2(2b+5)

We multiply parentheses

4b+10

Back to the equation:

-(4b+10)



We get rid of parentheses

6b-4b-10+2=0

We add all the numbers together, and all the variables

2b-8=0

We move all terms containing b to the left, all other terms to the right

2b=8

b=8/2

b=4

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