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-32=3+5(c-9)
We move all terms to the left:
-32-(3+5(c-9))=0
We calculate terms in parentheses: -(3+5(c-9)), so:We get rid of parentheses
3+5(c-9)
determiningTheFunctionDomain 5(c-9)+3
We multiply parentheses
5c-45+3
We add all the numbers together, and all the variables
5c-42
Back to the equation:
-(5c-42)
-5c+42-32=0
We add all the numbers together, and all the variables
-5c+10=0
We move all terms containing c to the left, all other terms to the right
-5c=-10
c=-10/-5
c=+2
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