4(3x-8)=-32+12x

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Solution for 4(3x-8)=-32+12x equation: 



4(3x-8)=-32+12x

We move all terms to the left:

4(3x-8)-(-32+12x)=0

We add all the numbers together, and all the variables

4(3x-8)-(12x-32)=0

We multiply parentheses

12x-(12x-32)-32=0

We get rid of parentheses

12x-12x+32-32=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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