4(4x-7)-4=4(x-3)+40

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Solution for 4(4x-7)-4=4(x-3)+40 equation: 



4(4x-7)-4=4(x-3)+40

We move all terms to the left:

4(4x-7)-4-(4(x-3)+40)=0

We multiply parentheses

16x-(4(x-3)+40)-28-4=0



We calculate terms in parentheses: -(4(x-3)+40), so:

4(x-3)+40

We multiply parentheses

4x-12+40

We add all the numbers together, and all the variables

4x+28

Back to the equation:

-(4x+28)



We add all the numbers together, and all the variables

16x-(4x+28)-32=0

We get rid of parentheses

16x-4x-28-32=0

We add all the numbers together, and all the variables

12x-60=0

We move all terms containing x to the left, all other terms to the right

12x=60

x=60/12

x=5

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