2(3a-5)(-2a=3)

Solution for 2(3a-5)(-2a=3) equation:

2(3a-5)(-2a=3)

We move all terms to the left:

2(3a-5)(-2a-(3))=0

We multiply parentheses ..

2(-6a^2-9a+10a+15)=0

We multiply parentheses

-12a^2-18a+20a+30=0

We add all the numbers together, and all the variables

-12a^2+2a+30=0

a = -12; b = 2; c = +30;
Δ = b2-4ac
Δ = 22-4·(-12)·30
Δ = 1444
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1444}=38$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-38}{2*-12}=\frac{-40}{-24}
=1+2/3
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+38}{2*-12}=\frac{36}{-24}
=-1+1/2
$