2/3m+4=1/4m

Solution for 2/3m+4=1/4m equation:

2/3m+4=1/4m

We move all terms to the left:

2/3m+4-(1/4m)=0


Domain of the equation: 3m!=0

m!=0/3

m!=0

m∈R



Domain of the equation: 4m)!=0

m!=0/1

m!=0

m∈R


We add all the numbers together, and all the variables

2/3m-(+1/4m)+4=0

We get rid of parentheses

2/3m-1/4m+4=0

We calculate fractions


8m/12m^2+(-3m)/12m^2+4=0

We multiply all the terms by the denominator


8m+(-3m)+4*12m^2=0

Wy multiply elements

48m^2+8m+(-3m)=0

We get rid of parentheses

48m^2+8m-3m=0

We add all the numbers together, and all the variables

48m^2+5m=0

a = 48; b = 5; c = 0;
Δ = b2-4ac
Δ = 52-4·48·0
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5}{2*48}=\frac{-10}{96}
=-5/48
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5}{2*48}=\frac{0}{96}
=0
$