6(x+4)-2x-4=2x+3(x-1)+10

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Solution for 6(x+4)-2x-4=2x+3(x-1)+10 equation: 



6(x+4)-2x-4=2x+3(x-1)+10

We move all terms to the left:

6(x+4)-2x-4-(2x+3(x-1)+10)=0

We add all the numbers together, and all the variables

-2x+6(x+4)-(2x+3(x-1)+10)-4=0

We multiply parentheses

-2x+6x-(2x+3(x-1)+10)+24-4=0



We calculate terms in parentheses: -(2x+3(x-1)+10), so:

2x+3(x-1)+10

We multiply parentheses

2x+3x-3+10

We add all the numbers together, and all the variables

5x+7

Back to the equation:

-(5x+7)



We add all the numbers together, and all the variables

4x-(5x+7)+20=0

We get rid of parentheses

4x-5x-7+20=0

We add all the numbers together, and all the variables

-1x+13=0

We move all terms containing x to the left, all other terms to the right

-x=-13

x=-13/-1

x=+13

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