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(7x+9=14)x2
We move all terms to the left:
(7x+9-(14)x2)=0
We add all the numbers together, and all the variables
(+7x-14x^2+9)=0
We get rid of parentheses
-14x^2+7x+9=0
a = -14; b = 7; c = +9;
Δ = b2-4ac
Δ = 72-4·(-14)·9
Δ = 553
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{553}}{2*-14}=\frac{-7-\sqrt{553}}{-28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{553}}{2*-14}=\frac{-7+\sqrt{553}}{-28} $
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