2(3-2x)=3(4x+1)

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Solution for 2(3-2x)=3(4x+1) equation: 



2(3-2x)=3(4x+1)

We move all terms to the left:

2(3-2x)-(3(4x+1))=0

We add all the numbers together, and all the variables

2(-2x+3)-(3(4x+1))=0

We multiply parentheses

-4x-(3(4x+1))+6=0



We calculate terms in parentheses: -(3(4x+1)), so:

3(4x+1)

We multiply parentheses

12x+3

Back to the equation:

-(12x+3)



We get rid of parentheses

-4x-12x-3+6=0

We add all the numbers together, and all the variables

-16x+3=0

We move all terms containing x to the left, all other terms to the right

-16x=-3

x=-3/-16

x=3/16

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