2+2=4y2*2=4y2+2=110

Solution for 2+2=4y2*2=4y2+2=110 equation:

2+2=4y^2*2=4y^2+2=110

We move all terms to the left:

2+2-(4y^2*2)=0

We add all the numbers together, and all the variables

-(4y^2*2)+4=0

We get rid of parentheses

-4y^2*2+4=0

Wy multiply elements

-8y^2+4=0

a = -8; b = 0; c = +4;
Δ = b2-4ac
Δ = 02-4·(-8)·4
Δ = 128
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{128}=\sqrt{64*2}=\sqrt{64}*\sqrt{2}=8\sqrt{2}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{2}}{2*-8}=\frac{0-8\sqrt{2}}{-16}
=-\frac{8\sqrt{2}}{-16}
=-\frac{\sqrt{2}}{-2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{2}}{2*-8}=\frac{0+8\sqrt{2}}{-16}
=\frac{8\sqrt{2}}{-16}
=\frac{\sqrt{2}}{-2}
$