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-2x-3x(6x-11)=7
We move all terms to the left:
-2x-3x(6x-11)-(7)=0
We multiply parentheses
-18x^2-2x+33x-7=0
We add all the numbers together, and all the variables
-18x^2+31x-7=0
a = -18; b = 31; c = -7;
Δ = b2-4ac
Δ = 312-4·(-18)·(-7)
Δ = 457
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{457}}{2*-18}=\frac{-31-\sqrt{457}}{-36} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{457}}{2*-18}=\frac{-31+\sqrt{457}}{-36} $
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