3(2k-7)=21

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Solution for 3(2k-7)=21 equation: 



3(2k-7)=21

We move all terms to the left:

3(2k-7)-(21)=0

We multiply parentheses

6k-21-21=0

We add all the numbers together, and all the variables

6k-42=0

We move all terms containing k to the left, all other terms to the right

6k=42

k=42/6

k=7

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