(3/5)e-6=(-2/5)(e-10)-7

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Solution for (3/5)e-6=(-2/5)(e-10)-7 equation: 



(3/5)e-6=(-2/5)(e-10)-7

We move all terms to the left:

(3/5)e-6-((-2/5)(e-10)-7)=0



Domain of the equation: 5)e!=0

e!=0/1

e!=0

e∈R





Domain of the equation: 5)(e-10)-7)!=0

e∈R



We add all the numbers together, and all the variables

(+3/5)e-((-2/5)(e-10)-7)-6=0

We multiply parentheses

3e^2-((-2/5)(e-10)-7)-6=0

We multiply parentheses ..

3e^2-((-2e^2-2/5*-10)-7)-6=0

We multiply all the terms by the denominator


-2e^2+3e^2*5*-2-10)-7)-((-6*5*-10)-7)=0

We add all the numbers together, and all the variables

-2e^2+3e^2*5*-2-10)-7)-(300-7)=0

We add all the numbers together, and all the variables

-2e^2+3e^2*5*=0

Wy multiply elements

-2e^2+15e^3=0

We do not support eepression: e^3

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