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2(3+x)=5(x+1)
We move all terms to the left:
2(3+x)-(5(x+1))=0
We add all the numbers together, and all the variables
2(x+3)-(5(x+1))=0
We multiply parentheses
2x-(5(x+1))+6=0
We calculate terms in parentheses: -(5(x+1)), so:We get rid of parentheses
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
2x-5x-5+6=0
We add all the numbers together, and all the variables
-3x+1=0
We move all terms containing x to the left, all other terms to the right
-3x=-1
x=-1/-3
x=1/3
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