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x(4x+12)=315
We move all terms to the left:
x(4x+12)-(315)=0
We multiply parentheses
4x^2+12x-315=0
a = 4; b = 12; c = -315;
Δ = b2-4ac
Δ = 122-4·4·(-315)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5184}=72$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-72}{2*4}=\frac{-84}{8} =-10+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+72}{2*4}=\frac{60}{8} =7+1/2 $
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